Đặt \(A=3^{30}-3^{29}+3^{28}-...-3^1+3^0\)
\(3A=3^{31}-3^{30}+3^{29}-...-3^2+3^1\)
\(3A+A=\left(3^{31}-3^{30}+3^{29}-...-3^2+3^1\right)+\left(3^{30}-3^{29}+3^{28}-...-3^1+3^0\right)\)
\(4A=3^{31}-3^0\)
\(A=\frac{3^{31}-1}{4}\)
Chúc bạn học tốt ~
cảm ơn bạn T.T
Thank you very much! T.T