Các câu hỏi tương tự
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
27x : 3x = 9
1/2 x 2x + 4 x 2x = 9 x 25
Tim x
Tìm x,y biết:
1) 3^X-1 = 1/243
2) 81^-2X x 27^X=9^5
3) ( x-y+3)^2 + (y-1)^2=0
tìm x
3^x-1=1/243
81^-2x.27^x=9^5
2^x+2^x+3=144
Tìm x biết a) 2x+2^(x+3) =144
b) 81^(-2x)*27^x =9^5
tìm x, biết:
a. 2 . 3x - 405 = 3^x - 1
b.(1/81)^x . 27^2x = (-9)^4
2^X + 2^X+3= 288 (2x-1)^3=27 (x+5)^3= -64 (2x -3)^2=9
Tìm x
a) (x+1)3 = 82
b) 92x-3 = 273x+1
Tìm X
a) (|x| - 1/8) . (-1/8)5 = (-1/8)7
b) (2x -3)2 = 25
c) 27/3x = 3
d) 9x-1 = 1/9