Question

3^2x+1=27

 

Answer 1

\(3^{2x+1}=27\)

\(3^{2x+1}=3^3\)

\(\Rightarrow2x+1=3\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

Answer 2

3^2x+1=27

3^2x+1=3^3

=> 2x+1=3

    2x      = 3-1

   2x       =  2

     x       = 1.

Answer 3

3^2x+1=27

3^2x+1=3³

2x+1=3

2x=3+1=4

x=4:2=2