Question

3^2x-1₌ \(\frac{1}{729}\)         

Answer 1

\(3^{2x-1}=\frac{1}{729}=\frac{1}{3^6}=3^{-6}\Rightarrow2x-1=-6\Leftrightarrow2x=-5\Leftrightarrow x=-\frac{5}{2}\)

\(\text{Vậy:}x=-\frac{5}{2}\)