\(\left(3^{2003}+3^{2000}\right):3^{2000}\)
\(=3^{2003}:3^{2000}+3^{2000}:3^{2000}\)
\(=3^3+1\)
\(=9+1\)
\(=10\)
(32003 + 32000) : 32000
= 32003 : 32000 + 32000 : 32000
= 33 + 1 = 27 +1 = 28
(32003+32000):32000
= 32003 :32000 + 32000:32000
= 33 + 1
= 9 + 1
= 10
k nha,thank you