-32-(x-5)=0
-32-x+5=0
-32-x=0-5
-32-x=-5
x=-32+5
x=-27
-32-(x-5)=0
-32-x+5=0
-32-x=0-5
-32-x=-5
x=-32+5
x=-27
Ta có: -32-(x-5) = 0
=> 32 + x - 5 = 0
=> 32+x = 5
=> 32 + x = 5
=> x = 5 - 32
=> x = -27
Vậy x = -27
-32-(x-5)=0
-32-x+5=0
-32-x=0-5
-32-x=-5
x=-32+5
x=-27
-32-(x-5)=0
-32-x+5=0
-32-x=0-5
-32-x=-5
x=-32+5
x=-27
Ta có: -32-(x-5) = 0
=> 32 + x - 5 = 0
=> 32+x = 5
=> 32 + x = 5
=> x = 5 - 32
=> x = -27
Vậy x = -27
(x –15) .15 = 0 b) 32 (x –10 ) = 32
c) ( x – 5)(x – 7) = 0 d) (x – 35).35 = 35
Tìm x eN biết
a) (x –15) .15 = 0 b) 32 (x –10 ) = 32 c/ ( x – 5)(x – 7) = 0 d/ (x – 35).35 = 3
(-32)-(x-5)=0
-32-(x-5)=0
5-(10-x)=7
-32-(x-5)=0
a, 32 . ( x - 10) = 32
b, ( x - 105 ) : 21 = 15
c, ( x - 5 ) . ( x - 7 ) = 0
[(5^6 : 5^3 -2^2.2^3)^0]^2011
32+5.[1^2012+2^2.2012^0]=4^2.3
321- 21. [(2.3^3+4^4 :32)]- 52
2018^0+5^9:5^7-3.7
BÀI 4 . TÌM x
1 . X + 5 . 2 - { 32 + 16 . 3 : 6 } = 0
2 . { X -1 }^ 5 = 32
3 . { 2X - 3 }^ 2 = 25