\(\frac{3x}{10}+\frac{5}{2}+\frac{3}{5}=\frac{5}{2}\)
=> \(\frac{3}{10}x=-\frac{3}{5}\)
=>x=-2
\(\left[30\%x+2+\frac{1}{2}\right]+\frac{3}{5}=2+\frac{1}{2}\)
\(\left[30\%x+\frac{5}{2}\right]+\frac{3}{5}=\frac{5}{2}\)
\(30\%+\frac{5}{2}=\frac{5}{2}-\frac{3}{5}\)
\(30\%x+\frac{5}{2}=\frac{19}{10}\)
\(\frac{3}{10}x=\frac{19}{10}-\frac{5}{2}\)
\(\frac{3}{10}x=\frac{-3}{5}\)
\(x=\frac{-3}{5}:\frac{3}{10}\)
\(x=-2\)
Vậy x=-2
(30%x + 2 + 1/2) + 3/5 = 2 + 1/2
30%x + 2 + 1/2 + 3/5 = 2 + 1/2
0,3x + 1/2 + 3/5 = 1/2
0,3x + 11/10 = 1/2
0,3x = 1/2 - 11/10
0,3x = -3/5
x = -3/5 : 0,3
x = -2
