\(-\left(30-2x\right)-\left(55+6x\right)=45+x\\ \Rightarrow-30+2x-55-6x-45-x=0\\ \Rightarrow\left(2x-6x-x\right)+\left(-30-55-45\right)=0\\ \Rightarrow-5x-130=0\\ \Rightarrow x=\dfrac{0+130}{-5}=-26\)
Bài 1: Tìm x
a) 5x - 7 = -19 + 2x
b) 35- 3x= 45 - 4x
c) 4x - 15 = - 75 - x
d) x - 12 = ( - 9 ) - 15
Bài 2 : Tìm x
a) 11- ( 15 + 14 ) = x - ( 25 - 9 )
b) 4x - 6 = - 20 + 3x
c) 45 - 2x = 55 - 5x
d) 6x - 15 =- 55 - 2x
45 + 6 x 17 + 55 + 2x 3 x 83
1+2+...+x=55
2+4+...+2x=2010
6x+4x=2010
3x+2{45-x-3[3x+7]-2x}+4x=55
E) {- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
{-3+2.[45-x-3(3x+7)-2x]+4x}=55-103-57:[-2(2X-1)^2-(-9)^0]=-106
Tìm số nguyên x :
{- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
Tìm số nguyên x, biết:
-{-3x+2[45-x-3(3x+7)-2x]+4x}=55
Tìm số nguyên x:
a,-2x+15<3x-7<19-x
b,-2x +3.{12-2[3x-(20+2x)-4x]+1}=45
c,{-3x+2.[45-x-3(3x 7)-2x] 4x}=55
Ai làm nhanh và đúng, mik tick
