Question

3-(x+2và 1\2-3 và 1\4 ):16 và 1\2 =2

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Answer 1

Đề: Tìm x

\(3-\left(x+2\frac{1}{2}-3\frac{1}{4}\right):16\frac{1}{2}=2\)

\(\left(x+\frac{5}{2}-\frac{13}{4}\right):\frac{33}{2}=3-2\)

\(\left(x+\frac{10}{4}-\frac{13}{4}\right):\frac{33}{2}=1\)

\(x+\frac{-3}{4}=\frac{33}{2}\)

\(x=\frac{33}{2}+\frac{3}{4}\)

\(x=\frac{66}{4}+\frac{3}{4}\)

\(x=\frac{69}{4}\)

Vậy \(x=\frac{69}{4}.\)

Answer 2

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