\(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}\left(5+1\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=162:6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=2\)
Vậy x =2
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