#)Giải :
Gọi tổng trên là A
\(A=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{40.43}\)
\(A=3-\frac{3}{4}+\frac{3}{4}-\frac{3}{7}+\frac{3}{7}-\frac{3}{10}+...+\frac{3}{40}-\frac{3}{43}\)
\(A=3-\frac{3}{43}\)
\(A=3\frac{3}{43}=\frac{132}{43}\)
#~Will~be~Pens~#