\(a,n_{H_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
\(PTHH:Zn+H_2SO_4\rightarrow ZnSO_4+H_2\\ ..........0,15.......0,15.......0,15.......0,15\left(mol\right)\)
\(m_{Zn}=65\cdot0,15=9,75\left(g\right)\)
\(b,m_{H_2SO_4}=98\cdot0,15=14,7\left(mol\right)\\ c,m_{dd_{H_2SO_4}}=\dfrac{14,7\cdot100}{20}=\dfrac{147}{2}\left(g\right)\\ d,C\%_{dd_{ZnSO_4}}=\dfrac{0,15\cdot161}{\dfrac{147}{2}}\cdot100\approx32,86\%\)