Question

3 chia hết cho (x+2)

Answer 1

=> x+2=Ư(3)={+ 1 ; + 3}

=>x={-5;-3;-1;1}

Answer 2

3 chia hết cho (x+2)

=>(x+2) E Ư(3)

=>Ư(3)={1;3;-1;-3}

=>x+2=1

x=-1

=>x+2=3

x=1

=>x+2=-1

x=-3

=>x+2=-3

x=-5

vay x E{-1;1;-3;-5}

 

Answer 3

3 chia hết cho x+2
<=> x+2\(\in\) Ư(3)
<=> x+2\(\in\){-3,-1,1,3}
<=>x\(\in\){-5,-3,-2,1}