\(3-|2x-4|=2x\)
\(|2x-4|=3-2x\)
\(\Rightarrow\hept{\begin{cases}2x-4=3-2x\\2x-4=-\left(3-2x\right)\end{cases}}\)
Xét \(2x-4=3-2x\)
\(2x+2x=3+4\)
\(4x=7\)
\(x=\frac{7}{4}\)
Xét \(2x-4=-\left(3-2x\right)\)
\(2x-4=-3+2x\)
\(2x-2x=-3+4\)
\(0x=-1\)
Vậy \(x=\frac{7}{4}\)