\(3-2\sqrt{x}=-1\)
\(\Leftrightarrow-2\sqrt{x}=-4\)
\(\Leftrightarrow\sqrt{x}=2\)
\(\Leftrightarrow x=4\)
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Các câu hỏi tương tự
1. Tìm x:
a/\(\sqrt{\dfrac{x-1}{x-3}=2}\)
b/\(\sqrt{\left(x-2\right)^2=7}\)
2. Tính:
\(\dfrac{\sqrt{6}+\sqrt{10}}{3+\sqrt{15}}\)
Rút gọn : A=\(\left(1-\frac{\sqrt{x}}{\sqrt{x}+1}\right):\left(\frac{2+\sqrt{x}}{x-5\sqrt{x}+6}+\frac{3+\sqrt{x}}{\sqrt{x}-2}-\frac{2+\sqrt{x}}{\sqrt{x}-3}\right)\)
Cho A=\(\left(1-\frac{\sqrt{x}}{\sqrt{x}+1}\right):\left(\frac{2+\sqrt{x}}{x-5\sqrt{x}+6}+\frac{3+\sqrt{x}}{\sqrt{x}-2}-\frac{2+\sqrt{x}}{\sqrt{x}-3}\right)\)
Tìm tập xác định và rút gọn A
1. Chứng minh:\(\left(\frac{x\sqrt{x}+27y\sqrt{y}}{3\sqrt{x}+9\sqrt{y}}-\sqrt{xy}\right).\left(\frac{3\sqrt{x}+9\sqrt{y}}{9y-x}\right)^2>\sqrt{8}\)
2. Rút gọn A= \(\frac{\sqrt{a+2\sqrt{a-1}}+\sqrt{a-2\sqrt{a-1}}}{\sqrt{a+\sqrt{2a-1}}-\sqrt{a-\sqrt{2a-1}}}\)
a,-12:(3/4-5/6)^2
,b,10.\(\sqrt{0.01}.\sqrt{\dfrac{16}{9}+3\sqrt{49}-\dfrac{1}{6}\sqrt{4}}\)
c,x/6=y/3=z/2 và x-2y+4z=8
d,|1/4+x|-1/3=2/5
a,
\(x=3\sqrt{2
}\)
\(y=2\sqrt{3}\)
b,
\(x=\sqrt{3}+\sqrt{6}\)
\(y=\sqrt{2}+\sqrt{7}\)
c,
\(x=-\frac{1}{2}\sqrt{\frac{1}{3}}\)
\(y=-\frac{1}{3}\sqrt{-\frac{1}{2}}\)
Mai tui nộp bài này r, TL hết nha pls
a)\(\sqrt{x=2}\)
b)\(\sqrt{\frac{x}{2}}=3\)
c)\(\sqrt{\frac{x}{2}}=\sqrt{\frac{y}{3}}\)và \(\sqrt{x}-\sqrt{y}=-1\)
d)\(\sqrt{\frac{x-3}{3}}=\sqrt{\frac{y-1-2}{4}}\)và \(\sqrt{x}=\sqrt{y-1}\)
Tìm x thuộc Z
a, \(\frac{\sqrt{x}-3}{\sqrt{x}+1}\)
b, \(\frac{2\left(\sqrt{2}-5\right)}{\sqrt{x}+1}\in Z\)
c, \(\frac{2\sqrt{x}+1}{3\sqrt{x}-1}\in Z\)
d, \(\frac{\sqrt{x}-2}{\sqrt{x}+2}\in Z\)
Tìm x biết:
a)\(\left|\sqrt{2}-x\right|=\sqrt{2}\)
b)\(\left|x-1\right|=\sqrt{3}+2\)
c)\(\left|1-2x\right|=\sqrt{5}-1\)
d)\(\left|1-x\right|=\sqrt{2}-0,\left(1\right)\)
e)\(\left|x-\sqrt{3}\right|=\sqrt{3}-1\)
f)\(\left|x-\sqrt{2}\right|=1,\left(4\right)\)
\(2x=\sqrt{3+\frac{1}{2}\sqrt{3+\frac{1}{2}\sqrt{3+\frac{1}{2}\sqrt{x+3}}}}\)