\(2x.\left(x-\frac{1}{3}\right)=0\)
\(x-\frac{1}{3}=0\)
\(x=\frac{1}{3}\)
Vậy \(x=\frac{1}{3}\)
2x.(x - 1/3) = 0
=> 2x = 0 hoặc x - 1/3 = 0
=> x = 0 hoặc x = 1/3
Vậy x thuộc {0 ; 1/3}
Tìm x, biết
a)(2x-1)^5-(2x-1)^8=0
b)(2x+1). (2x-3)<0
c)(x-1). (2x+3)>0
|x-3| + |y-2x | =0 |x| + 3|2x -x ² | =0 |5x ² -5 | + 4|y-7 | =0 ||x +1 | + |y-5 |=0 |x ² -1| + |y-1| =0 |x-1 | +|x ²-x |=0
Bài 3: Tìm x biết:
a. \(2x+10=0\)
b. \(-2x+5=0\)
c. \(4-x=0\)
d. \(2x+1=0\)
e. \(x^2+2=0\)
f. \(2x+x=0\)
tìm x thoả mãn
(2x-1)(2x-5)<0
(3-2x)(x+2)>0
(3x+1)(5-2x)>0
mình đang rất cần
-5x(x+1/5)-1/2x(x-2/3)=3/2
(x+1)x(x-3)=0
(3x-1)x(-1/2x+5)=0
Tìm x
(3^2-2^3)x+3^2.2^2=4^2.3
x^5-x^3=0
(x-1)^2+(-3)^2=5^2.(-1)^100
(2x-1)^2-(2x-1)=0
a,/1-4x/=2x-3
b,/2x/+3=5-2x
c,/3x-1/=6
d,x(x+2/3)=0
x-(x-1/2)=0
các bn giúp mk vs
2x-3=x+1/2
4x-(x+1/2)=2x-(1/2-5)
2/3-1/3(x-2/3)-1/2(2x+1)=5
(x+1/2).(x-3/4)=0
(2x-1).(3x+1/5)=0
4x^2 -2x=0
ai giúp mik, cho 10 like VIỆT NAM nói là làm
Tìm x,y nguyên:
1) (2x-1).(2x-5)<0
2) (3x+1).(5-2x)>0
3) (3-2x).(x+2)>0
4) (2-x).(x+1)=|y+1|
5) (x+3).(1-x)=|y|
6) (x-2).(5-x)=|2y+1|+2
7)(x-3).(x-5)+|y-2|=0
8) (x-2).(5-x)-|y+1|=1
GIÚP MK VS MK TICK CHO
THANK FOR WATCHING!
Tìm x biết :
a. 3(2x+3)(3x-5)<0 ; b. x2+1>0 ; c. (x2+1)(2x-5)>0 ; d. x2+2x<0
