=> 2x/5-1 = 1/7 .5=5/7
=> 2x/4 = 5/7
=> 14x/28 = 20/28
=> 14x=20
=> x=20:14=10/7
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tìm x biết:
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[2x+3/5]2 - 9/25=0
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tính C=1/3*5+1/5*7+1/7*9+............+1/(2X+1)(2X+3)=15/93
a,2/5+3/7+-3/5
b,1-5/7:x=-1/3
c,4/5*(x-1/3)=15/8
d,2/3:(2x+1/8)=7/3
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giúp mình với
tìm x biết1\3*5+1\5*7+1\7*9+....+1\(2x+1)(2x+3)
Tìm x
a. 2x + ( 1 - 5 )^2 = 7
b. | 1/2x + 1 | + 5 = 1/2
c. | 3x + 1/2 | - 1/3 = 1/3
d. | 2x - 3 | = 7/5
1/3 x 5 + 1/5 x 7 + 1/7 x 9+ ... + 1/(2x + 1) x (2x + 3) = 15/93.tinh x
1/3×5 +1/5×7 +.......+1/2x+1×2x+3=15/93
Tìm x :
A)2x-3/7=6 2/7
B)3 1/3+5/6x=3 1/2
C)2x+30%.x=-4 3/5
D)2/3-|x-1/5|=5/9
bài 3
d) \(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
e) \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+2}}{131}\)
Tìm x biết
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)