\(2x=3y=5z\Rightarrow\frac{x}{15}=\frac{y}{10}=\frac{z}{6}\)(Cùng chia cho 30 )
Áp dụng t/c dãy tsbn \(\frac{x}{15}=\frac{y}{10}=\frac{z}{6}=\frac{x+y-z}{15+10-6}=\frac{95}{19}=5\)
\(\Rightarrow\hept{\begin{cases}x=5.15=75\\y=5.10=50\\z=5.6=30\end{cases}}\)
Ta có 2x=3y=5z
\(\Rightarrow\frac{2x}{30}=\frac{3y}{30}=\frac{5z}{30}\)
\(\Rightarrow\frac{x}{15}=\frac{y}{10}=\frac{z}{6}=\frac{x+y-z}{15+10-6}=\frac{95}{19}=5\)
\(\frac{x}{15}=5\Rightarrow x=75\)
\(\frac{y}{10}=5\Rightarrow y=50\)
\(\frac{z}{6}=5\Rightarrow z=30\)
Vậy x = 75 ; y = 50 ; z = 30