Question

2x=3y=5z và x-y+z=-33

Answer 1

Từ 2x=3y=5z =>x/3=y/2 ; y/5=z/3                                         áp dụng t/c dãy tỉ số = nhau ta có :

x/3=y/2 <=> x/3*1/5=y/2*1/5                                               x/15=y/10=z/6=x-y+z/15-10+6=-33/11=(-3)

            <=>x/15=y/10 (1)                                                   =>x/15=-3 <=>x=15*(-3)=(-45)

y/5=z/3 <=>y/5*1/2=z/3*1/2                                                    y/10=(-3) <=>y=10*(-3)=(-30)

              <=>y/10=z/6 (2)    => từ 1,2 có x/15=y/10=z/6            z/6=(-3) <=>z=6*(-3)=(-18)