\(\Rightarrow\left(3x-5\right)\left(2x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
\(\Leftrightarrow2x\left(3x-5\right)+\left(3x-5\right)=0\\ \Leftrightarrow\left(3x-5\right)\left(2x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}3x-5=0\\2x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=\dfrac{-1}{2}\end{matrix}\right.\)