2(x+3)-x(x+3)=0
(2-x) (x+3)=0
=> 2-x=0 hoac x+3=0
=>x=2 hoac x=-3
\(2\left(x+3\right)-x^2-3x=0\)
=>\(2\left(x+3\right)-x\left(x+3\right)=0\)
=>\(\left(2-x\right)\left(x+3\right)=0\)
=>\(\orbr{\begin{cases}2-x=0\\x+3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-3\end{cases}}}\)
2(x + 3) - x2 - 3x = 0
\(\Leftrightarrow\)2(x+3)-x(x+3)=0
\(\Leftrightarrow\)(2-x)(x+3)=0
\(\Leftrightarrow\)\(\orbr{\begin{cases}2-x=0\\x+3=0\end{cases}}\) \(\Leftrightarrow\) \(\orbr{\begin{cases}x=2\\x=-3\end{cases}}\)