\(\left(2x\right)^3=\frac{4^3}{4}\)
\(8x^3=4^2\)
\(x^3=4^2:8=2\)
\(x=\sqrt[3]{2}\)
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
Bài 4. Tìm x ∈ N biết:
a) x3 = 27 b) (2x – 1)3 = 8
c) (2x – 3)2 = 9 d) 2x + 5= 3^4 : 3^2
3^4 tức là 3 mũ 4
Giúp mình với nhé!
3/2.(x-1/2)-3/4=1/2x-1
5/2.(x-3/4)-1/2=1-2x
9/2-3(1/2x-1)-4=1/2x-2
5-3/4.(x-1/3)-4(x-2)=1-11/2
4/5.17-x-3/2x=13/4x
Mình cảm ơn!
a)2x – 12.4 = 28
b)128-3(x +4)= 23
c) 20 + 8.(x + 3) = 52 .4
d) (12x -4 3 ).83= 4.84
e) 720: [41-(2x-5)]=23 .5
f) (2x- 4)(x – 3) = 0
g) (2x +1)3= 5.25
h) 2 x . 4 = 128
i) 5x-2 = 1
k)2x + 2x + 3= 144
Tìm x:
a) |x|-3/4=5/3
b) |2x-1/3|+5/6=1
c) 17/2-|2x-3/4|=-7/4
d) |2x-1|=(-4) mũ 2
-3. (2x - 4) + 4( 3 - 2x)= -130
1) (x + 1/2).(2/3 - 2x) = 0 2) 2/3x + 1/2x = 5/2 : 3 và 3/4 3) (2x - 3)(6 - 2x)= 0 4) -5(x + 1/5) - 1/2(x - 2/3) = 3/2x - 5/6
rut gon
a,3x(2x-7)-3x(4x-5)
b,(-7x+8)(-2x+3)-7x(2x-4)
c,(2x-3)(3x2-2x+4)-(2x-3)(3x+4)
d,(-2+7)(3x-6)-(4x-5)(2x-6)
a, 2x+ 1/4 = 3/2
b, (x-5) - 1/3 = 2/5
c, (4,5-2x):3/4=4/3
Tìm x biết:
a) 12 ( 2x - 6 ) - 43= 5^3
b) 7 ( 25 - 3x ) = 3^4 - 2^5
c) ( 3x - 5 ) + 3^4 = 6^0 = 5^3
d) 3x + 2x ( 2^3 . 5 - 3^2 . 4 ) + 5^2 = 4^4
e) 720 : [ 41 - (2x - 5 ) ] = 2^3 .5
Bài 1Tìm x
A; 3 1/3 (3 1/4+2x)=6 2/3
B; x-25%x=6/11 (1/2+3/4-1/3)
C; (4,5-2x)×1 4/7=11/14
D; (-3)^2-|2x+3|=4