Question

2^x+2^x+2+2^x+4=336

Answer 1

\(2^x+2^x\cdot2^2+2^x\cdot2^4=336\)

\(\Leftrightarrow2^x\left(1+2^2+2^4\right)=336\)

\(\Leftrightarrow2^x\cdot21=336\)

\(\Leftrightarrow2^x=336:21=16\)

\(16=2^4\Rightarrow x=4\)

Answer 2

\(\Rightarrow2^x.\left(1+2^2+2^4\right)=336\)

\(\Rightarrow2^x.\left(1+4+16\right)=336\)

\(\Rightarrow2^x.21=336\)

\(\Rightarrow2^x=336:21\)

\(\Rightarrow2^x=16=2^4\)

Vậy x=4.

 

Answer 3

2^x+2^x+2 +2^x+4=336

=>2^x+2^x.2^2+2^x.2^4=336

=>2^x(1+2^2+2^4)=336

=>2^x .21=336

=>2^x=336:21=16

=>2^x=2^4=>x=4

Answer 4

\(2^x+2^{x+2}+2^{x+4}=336\)

\(2^x\left(1+2^2+2^4\right)=336\)

\(2^x\times21=336\)

\(2^x=336\div21\)

\(2^x=16\)

\(2^x=2^4\)

\(\Rightarrow x=4\)