\(2^x+2^{x+1}=48\)
\(2^x.1+2^x.2^1=48\)
\(2^x.\left(1+2\right)=48\)
\(2^x.3=48\)
\(2^x=48\div3\)
\(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
VẬy x =4
2x+2x+1=48
=>1.2x+2x.2=48
=> 2x.(1+2)=48
=> 2x.3=48
=> 2x=48:3
=> 2x=16
=>2x=24
=> x=4
Vậy x=4
\(2^x\)+\(2^{x+1}\)=\(48\)
\(2^x\)+\(2^x\).\(2\)=48
\(2^x\)(1+2)=48
\(2^x\).3=48
\(2^x\)=48:3
\(2^x\)=16
\(2^x\)=\(2^4\)
x=4
Vậy x=4
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