\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x+2^x.2+2^x.4+2^x.8=480\)
\(2^x.\left(1+2+4+8\right)=480\)
\(2^x.15=480\)
\(2^x=32\)
\(2^x=2^5\)
\(x=5\)
Vậy \(x=5\)
2x+2x+1+2x+2+2x+3=480
\(\Leftrightarrow2^x\left(1+2+2^2+2^3\right)=480\)
\(\Leftrightarrow2^x.15=480\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Leftrightarrow x=5\)
2x + 2x+1 + 2x+2 + 2x+3 = 480
2x . 1 + 2x . 2 + 2x . 22 + 2x . 23 = 480
2x . ( 1 + 2 + 22 + 23 ) = 480
2x . 15 = 480
2x = 480 : 15
2x = 32
2x = 25
=> x = 5