2x + 2x + 1 + 2x + 2 + 2x + 3 = 480
=> 2x.(1 + 2 + 4 + 8) = 480
=> 2x.15 = 480
=> 2x = 480 : 15
=> 2x = 32
=> 2x = 25
=> x = 5
có \(2^x+2^{x+1}+2^{x+2}+2^{x+3}=\)480
\(2^x\cdot1+2^x\cdot2+2^x\cdot4+2^x\cdot8=480\)
\(2^x\cdot\left(1+2+4+8\right)=480\)
\(2^x\cdot15=480\)
\(2^x=32\)
do đó x = 5
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Rightarrow2^x\times\left(1+2+4+8\right)=480\)
\(\Rightarrow2^x\times15=480\)
\(\Rightarrow2^x=480:15\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x\left(1+2+4+8\right)=480\)
\(2^x\cdot15=480\)
\(2^x=480\text{ : }15\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow\text{ }x=5\)
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x.\left(1+2+4+8\right)=480\)
\(2^x.15=480\)
\(2^x=480:15\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
~ Hok tốt ~