Ta có : 2^x + 2^x+1 + 2^x+2 + 2^x+3 = 480
=> 2^x . (1+2+2^2+2^3)=480
=> 2^x . 15=480
=> 2^x=480:15
=> 2^x=32
=> 2^x=2^5
=> x=5
Vậy x=5
Tk và kb với mk nha :)))
Ta có: \(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=480\)
\(\Rightarrow2^x.\left(1+2+2^2+2^3\right)=480\)
\(\Rightarrow2^x.15=480\)
\(\Rightarrow2^x=480\div15=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x = 5
2.x+2.x+1+2.x+2+2.x+3=480
2x+2x+2x+2x+<1+2+3>=480
x<2+2+2+2>+6=480
x.8+6=480
x.8=480-6=474
x=474:8
x=\(\frac{237}{4}\)