\(^{2^x}\)x \(^{2^2}\)- \(2^x\)x 1= 48
=> \(2^x\)x ( \(^{2^2}\)- 1 ) = 48
=> \(2^x\) x ( 4 - 1) = 48
=> \(2^x\)x 3 = 48
=> \(2^x\)= 48 : 3
=> \(^{2^x}\)= 16
=> \(2^x\)= \(2^4\)
=> x = 4
Vậy: x = 4
2x+2-2x=48
2x.22-2x=48
2x.4-2x=48
2x.3=48
2x=48:3
2x=16
2x=24
=>x=4