Ta có :
\(\left(2x+1\right)^3=27\)
\(\Rightarrow\left(2x+1\right)^3=3^3\)
\(\Rightarrow2x+1=3\)
\(\Rightarrow2x=3-1=2\)
\(\Rightarrow x=2:2=1\)
Vậy \(x=1\)
Ta có : \(\left(2x+1\right)^3=27\)
\(\left(2x+1\right)^3=3^3\)
2x + 1 = 3
2x = 2
x = 1
Vậy x = 1
\(\Rightarrow2\cdot x+1=3\\ \Rightarrow2\cdot x=2\\ \Rightarrow x=1\)
( 2x +1 )3 = 27
<=> ( 2x + 1)3 = 33
<=> 2x +1 = 3
<=> 2x = 3-1
<=> 2x = 2
<=> x = 2/2
<=> x = 1
Ghi đề rõ ràng nha bạn :
Theo đề : \(\left(2X+1\right)^3=27\)
\(\left(2X+1\right)^3=3^3\)
\(\Rightarrow2X+1=3\)
\(2X=3-1=2\) \(X=2:2=1\)
\(V\text{ậy}X=1\)
(2.x+1)3=27
Vì 3x3x3=27
=> x=1 vì (2x1+1)3=27
(2x+1)³=27
=>(2x+1)³=3³
=>2x+1=3
=>2x=3-1
=>2x=2
=>x=2:2
=>x=1
Vậy x=1