tìm x
a) x: 27=3,6
b)\(\dfrac{2x+1}{-27}\) =\(\dfrac{-3}{2x+1}\)
tìm x trong các tỉ lệ thức sau:
a,x:27=-2 : 3,6
b,2x+1/-27= -3/2x+1
(5-2x)/3=(4x-1)/-5
(12-3x)/32=6/(4-x)
(10-2x)/6=27/(5-x)
a) (2x-1)^3=27
b) (2x-1)^4=81
c) (x-2)^5=-32
d) (3x-1)^4=(3x-1)^6
đ) 5^x +5^x+2=650
g) 3^x-1 +5.3^x-1=162
a)3,8:(2x)=1/4:8/3
b) 6:(-27)=-11/4:117/4
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
Tìm x biết:
2x-1/3 = 27/2x-1
(1/81)x..272x=(-9)4
bai 1: Tim x
a) (x-1)^3 =27
b ( 2x +1)^2=25
c) (x-1)^x+2=(x-1)x+4
d) ( 2x-1)^3 =-8
e) 2^2x-2x=96
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