<=> 2x+1 * 3y = 22x * 3x
=> \(\hept{\begin{cases}x+1=2x\\x=y\end{cases}}\Rightarrow\hept{\begin{cases}x=1\\y=1\end{cases}}\)
2x+1.3y=12x
2x+1.3y=4x.3x
2x+1.3y=(22)x.3x
2x+1.3y=22x.3x
=> 3y:3x=22x:2x+1
=> 3y-x=2x-1
Mà (2,3)=1 => 3y-x=2x-1=1
=> y-x=0; x-1=0
=> x=y=1
Vậy x=y=1