Question

(2x+1)(3x-5)=4x^2-1

Answer 1

<=> 6x^2 - 7x - 5 = 4x^2 - 1 

<=> 2x^2 - 7x -4 =0 

<=> x = 4 ; x = -1/2 

Answer 2

6x²-10x+3x-5=4x²-1

6x²-10x+3x-5-4x²+1=0

2x²-7x-4=0

\(\Rightarrow\)\(\left\{{}\begin{matrix}x=4\\x=\dfrac{1}{2}\end{matrix}\right.\)

Answer 3

⇔ 6x² - 10x + 3x - 5 = 4x² - 1

⇔ 2x² - 7x - 4 = 0 

⇔ \(\left[{}\begin{matrix}x=4\\x=\dfrac{-1}{2}\end{matrix}\right.\)

Answer 4

6x²-10x+3x-5=4x²-1

6x²-10x+3x-5-4x²+1=0

2x²-7x-4=0