Question

(2x+1)+(2x+2)+...+(2x+2015)=0

Answer 1

(2x + 1) + (2x + 2) + ... + (2x + 2015) = 0

=> 2x + 1 + 2x + 2 + ... + 2x + 2015 = 0

=> 2015.2x + (2015 + 1).2015 : 2 = 0

=> 4030x + 2031120 = 0

=> 4030x = -2031120

=> x = -504

Answer 2

Có tất cả 2015 số hạng

Tổng là

(2x+1+2x+2015).2015:2=0

4x+2016=0

4x=-2016

x=(-2016):4=-504