Question

(2x+1)+(2x+2)+...+(2x+2015)=0

Answer 1

<=> ( 2x + 2x + 2x + .... + 2x ) + ( 1 + 2 + 3 + ... + 2015 ) = 0

<=> ( 2x . 2015 ) + [ 2015 . ( 2015 + 1 ) : 2 ] = 0

<=> 4030x + 2031120 = 0

<=> 4030x = 0 - 2031120 = - 2031120

<=> x = - 2031120 : 4030

=> x = - 504

Vậy x = - 504

Answer 2

ủng hộ mình nha