Question

(2x+1) + (2x+2) +.....+ (2x+2015) = 0

Answer 1

( 2x + 1 ) + ( 2x + 2 ) + ... + ( 2x + 2015 ) = 0

=> ( 2x + 2x + ...+ 2x ) + ( 1 + 2 + ... + 2015 ) = 0

                2015 số 2x

=> 2x . 2015 + 2031120 = 0

=> 2x . 2015 = 0 - 2031120 

=> 2x . 2015 = - 2031120

=> 2x = ( - 2031120 ) : 2015

=> 2x = - 1008

=> x = ( - 1008 ) : 2

=> x = - 504

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