\(2x\left(x-\frac{1}{7}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x=0\\x-\frac{1}{7}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{7}\end{cases}}}\)
Vậy x=0 hoặc x= 1/7
\(2x.\left(x-\frac{1}{7}\right)=0\)
\(x.\left(x-\frac{1}{7}\right)=0\)
\(x=0\)HOẶC \(x-\frac{1}{7}=0\)
\(x=0\)HOẶC \(x=\frac{1}{7}\)