Question

(2x-5)^2-(3-x)^2=0

Answer 1

\(\left(2x-5\right)^2-\left(3-x\right)^2=0\)

\(\left(2x-5-3+x\right).\left(2x-5+3-x\right)=0\)

\(\left(3x-8\right).\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}3x=8\\x=2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=2\end{matrix}\right.\)

Answer 2

\(\left(2x-5\right)^2-\left(3-x\right)^2=0\)

\(\left(2x-5-3+x\right)\left(2x-5+3-x\right)=0\)

\(\left(3x-8\right)\left(x-2\right)=0\)

\(=>\left[{}\begin{matrix}3x-8=0\\x-2=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=2\end{matrix}\right.\)