\(\left(2x-4\right).\left(3-x\right)=0\)
\(2x-4=0\)
\(3-x=0\)
\(x=2\)
\(x=3\)
( 2x - 4 ) . ( 3 - x ) = 0
\(\Rightarrow\) 2x - 4 = 0 hoặc 3 - x = 0
+ ) 2x - 4 = 0 + ) 3 - x = 0
2x = 0 + 4 x = 3 - 0
2x = 4 x = 3
x = 4 : 2
x = 2
vậy x = 2 ; x = 3
( 2x - 4 ) . ( 3 - x ) = 0
=> 2x - 4 = 0 hoặc 3 - x = 0 nên ta có 2 trường hợp
TH1 : 2x - 4 = 0
2x = 0 + 4
2x = 4
x = 4 : 2
x = 2
TH2 : 3 - x = 0
x = 0 + 3
x = 3