Question

(2x-3)^2=(x-5)(4x-3)
tìm x 
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Answer 1

\(\left(2x-3\right)^2=\left(x-5\right)\left(4x-3\right)\)

\(\Leftrightarrow4x^2-12x+9=4x^2-20x-3x+15\)

\(\Leftrightarrow4x^2-4x^2-12x+3x+20x=15-9\)

\(\Leftrightarrow11x=6\)

\(\Leftrightarrow x=\frac{6}{11}\)

Answer 2

(2x-3)^2=(x-5)(4x-3)

<=> 4x²- 12x+ 9= 4x²- 23x+ 15

<=> 4x²-12x+ 9- 4x²+ 23x- 15= 0

<=> 11x- 6= 0

<=> x= 6/11