(2x-3)2=49
(2x-3)2=72 hoặc (2x-3)2 = (-7)2
2x - 3 = 7 hoặc 2x - 3 = -7
Vậy x = 5 hoặc x = -2
\(\left(2x-3\right)^2=49\)
\(\Leftrightarrow\hept{\begin{cases}\left(2x-3\right)^2=7^2\\\left(2x-3\right)^2=\left(-7\right)^2\end{cases}}\)
\(\hept{\begin{cases}2x-3=7\\2x-3=-7\end{cases}}\)
\(\hept{\begin{cases}2x=10\\2x=-4\end{cases}}\)
\(\hept{\begin{cases}x=5\\x=-2\end{cases}}\)
\(\left(2x-3\right)^2=49\)
\(=>\sqrt{\left(2x-3\right)^2}=\sqrt{49}\)
\(=>2x-3=7\)
\(=>2x=10\)
\(=>x=5\)
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