\(\left(2x-3\right)^2=25\)
\(\left(2x-3\right)^2=5^2\)
\(\Rightarrow2x-3=5\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
\(\left(2x-3\right)^2=25\)
\(\Rightarrow2x-3=5\)
\(\Rightarrow x=4\)
1)(-1/2)^2:-1/4-2x(-1/2)^3+căn bậc 25-16
2)25^10x(1/5)^20+(-3/8)^8x(-4/3)^8-2021^0
(2x-3)^2=4/25
a) 5(x-2)(x+3)=1
b) 7(x-2024)2 = 23- y2
c) |x2+ 2x| + |y2- 9|= 0
d) 2x+ 2x+1+2x+2+2x+3=120
e) ( x- 7 )x+1- (x - 7)x+11=0
f) 25 - y2= 8(x 2012)2
Bài 5: Tìm nghiệm của các đa thức sau: Dạng 1: a) 4x + 9 b) -5x + 6 c) 7 – 2x d) 2x + 5 Dạng 2: a) ( x+ 5 ) ( x – 3) b) ( 2x – 6) ( x – 3) c) ( x – 2) ( 4x + 10 ) Dạng 3: a) x2 -2x b) x2 – 3x c) 3x2 – 4x d) ( 2x- 1)2 Dạng 4: a) x2 – 1 b) x2 – 9 c)– x 2 + 25 d) x2 - 2 e) 4x2 + 5 f) –x 2 – 16 g) - 4x4 – 25 Dạng 5: a) 2x2 – 5x + 3 b) 4x2 + 6x – 1 c) 2x2 + x – 1 d) 3x2 + 2x – 1
\(\dfrac{1}{3}\)x(2x-\(\dfrac{1}{3}\))\(^2\)-\(\dfrac{25}{27}\)=0
(2x-3)3 = -64
(2x-3)2 =25
(3x-4)2 =36
2x+1 = 64
a) 2x×3/5-5x=3/2-7x
b) (x-1/5)^2=4/25
TÌM X:
(2x+1)2 =25
(2x-3)2 =36
(2x+3)^2=25
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