\(=\frac{9}{40}nha.ban\)
Tìm x đúng không ạ?
\(\frac{2x}{-3}-\left(-\frac{6}{40}\right)=0\)
\(\frac{2x}{-3}=0+\left(-\frac{6}{40}\right)\)
\(\frac{2x}{-3}=-\frac{6}{40}\)
⇒\(2x\cdot40=\left(-3\right)\cdot\left(-6\right)\)
⇒ \(2x=\frac{\left(-3\right)\cdot\left(-6\right)}{40}\)
⇒ \(2x=0,45\)
⇒ \(x=0,45:2\)
⇒ \(x=0,225\)
#Kochou-Shinobu
\(\frac{2x}{-3}-\frac{-6}{40}=0\Rightarrow\frac{2x}{-3}=\frac{-6}{40}\)(2 phân số trừ cho nhau =0)
\(\Rightarrow2x.40=-6.\left(-3\right)\)
\(2x.40=18\)
\(2x=18:40=\frac{18}{40}=\frac{9}{20}\)
\(x=\frac{9}{20}:2=\frac{9}{20}.\frac{1}{2}=\frac{9}{40}\)
đúng thì cho mik nha
=> 2x/-3 =-6/40
=> -80x/120 = -18/120
=> -80x = -18 => x = (-18) : (-80) => x = 9/40