Ta có: |2x+3|=5
<=> 2x+3=5
2x+3=-5
<=> 2x=2
2x=-8
<=> x=1
x=-4
I 2x + 3 I = 5
=> 2x = 5 - 3
=> 2x = 2
=> x = 2 : 2
=> x = 1
Suy ra 2x+3 = 5 suy ra 2x = 5 - 3 =2 suy ra x = 2 : 2 = 1
hoặc 2x+3 = - 5 suy ra 2x = -5 - 3 = -8 suy ra x = -8 : 2 = -4
Vậy x = 1 ; x = -4
TH1:2x+3=5
=>2x=5-3
=>2x=2
=>x=2/2=1
TH2: 2x+3=-5
=>2x=-5-3
=>2x=-8
=>x=-8/2=-4
Vậy x=-4;1
l 2x + 3 l = 5
+, 2x+3=5 +, 2x + 3 = -5
2x=5-3 2x = (-5) - 3
2x=2 2x = -8
x=2:2 x = (-8) : 2
x=1 x = -4
Vậy x=1 hoặc x=-4
Ta có: |2x+3|=5
<=> 2x+3=5
2x+3=-5
<=> 2x=2
2x=-8
<=> x=1
x=-4
Ta có: |2x+3|=5
<=> 2x+3=5
2x+3=-5
<=> 2x=2
2x=-8
<=> x=1
x=-4
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