2x+2x+4=272
=>2x+2x.24=272
=>2x.(24+1)=272
=>2x.17=272
=>2x=272:17
=>2x=16
=>2x=24
=>x=4
ta có: \(2^x+2^{x+4}=272\)
\(\Rightarrow2^x\left(1+2^4\right)=272\)
\(\Rightarrow2^x\times17=272\)
\(\Rightarrow2^x=272\div17\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)