2x + 2x+1 = 24
2x(1+2) = 24
2x.3 = 24
=> 2x = 8 = 23
=> x = 3
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2x + 2x+1 = 24
2x(1+2) = 24
2x.3 = 24
=> 2x = 8 = 23
=> x = 3
\(\frac{2x+1}{6}=\frac{24}{2x+1}\)
1) Tìm x biết:
a)-(2x-16)-(x-8)=24
b)-3.(-x-4)-x=42-24
c)|2x-4|-16=-8
a,-13x=39 b,2x-(-17)=15
c,-7-2x=37-(-24) d,-2(2x+1)=-5(x+1)
1/3: (2x-1)=-4/24
1.tìm x \(\in Z\)
a) 61 + ( x - 562)=81
b) (562) -(x - 568)=0
c) 62 + (2x - 123)=283
d) (2x - 1).12=24
3+2x-1=24-[42-(22-1)]
(2x+1)(y+1)=24
Câu 3 (1,5 điểm). Tìm x, biết:
a) x + 2006 = 2021
b) 2x – 2016 = 24 x 4
c) 3(2x + 1)3 = 81
TIM X THUOC N, BIET
a,12 CHIA HET 2X +1
b, 24 chia het 2X -1
Bài 8. Tìm x ϵ N biết:
a) x3=27
b) (2x-1)3=8
c) (x-2)2=16
d) (2x – 3)2=9
e) 2x+5=34:32
f) (3x-24).73=2.74