nếu 2x-1=2x+2
2x-2x=2+1
0x=3
x không có giá trị
nếu 2x-1=-2x-2
2x+2x=-2+1
4x=-1
x=\(\frac{-1}{4}\)
vậy x= \(\frac{-1}{4}\)
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Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
Rút gọn các bt sau bang cach nhan nhat:
(2x^2+2x+1)(2x^2-2x^2+1)-(2x^2+1)^2
Dạng toán mới đây
Ta có: 2x(x + 1) :: x + 1 => 2x^2 + 2x :: x + 1 => (2x^2 + 3x + 2) - (2x^2 + 2x) :: x + 1 => x + 2 :: x + 1 => (x + 2) - (x + 1) :: x + 1 => 1 :: x + 1.
tìm đề bài toán
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )30 b) 2x(3-2x) + 2x(2x-1)15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)1 d) (x+2) (x+2)- (x -3)(x+1) 9
e) (4x+1)(6x-3) 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) 14
Đọc tiếp
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
b1:
[4+2x]=-3x [3x-1]+2=x
[x+15]+1=3x [2x-5]+x=2
b2:
[2x-5]=x+1 [3x-2]-1=x
[3x-7]=2x+1 [2x-1]+1=x
(2x-1).(4x2+2x+1)-(3+2x).(3+2x).(3+2x)+36.(x-1).(x-1)
Tìm x biết
/2x-1/-2x=1
/3x-1/=1-3x
/2x-2/=2x-2
tìm x
/2x+3/+/x+2/=4x
/2x-1/+/1-2x/=8
/2x^2+/x-5//=2x^2+5
C=(2x-2)(3x+3)<0
D=(3x+1)(2x-2)>0
E=(1-2x)(2+5x)<0
G=2x-1/3x-1>0
H=-2x+1/x-2<0
1:Tìm x, biết:
a) (3/5)^2x-1 = 125/27
b)1/2+(1/2.3)+(1/3.4)+...+(1/2015.2016)-2x=1/2-1/2016
c)/2x^2+/x-2//=2x^2+3