Question

(2x – 1)² – (x – 5)² =0 

làm sao mn

Answer 1

\(\left(2x-1-x+5\right)\left(2x-1+x-5\right)=0\)

\(\left[{}\begin{matrix}x+4=0\\3x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=2\end{matrix}\right.\)

Answer 2

\(\Rightarrow\left(2x-1-x+5\right)\left(2x-1+x-5\right)=0\\ \Rightarrow\left(x+4\right)\left(3x-6\right)=0\\ \Rightarrow3\left(x-2\right)\left(x+4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Answer 3

\(\left(2x-1\right)^2-\left(x-5\right)^2=0\Leftrightarrow\left(2x-1-x+5\right)\left(2x-1+x-5\right)=0\Leftrightarrow\left(x+4\right)\left(3x-6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=2\end{matrix}\right.\)