Question

2x-10/4=5+2-2x/6

Answer 1

\(\dfrac{2x-10}{4}=5+\dfrac{2-2x}{6}\) ĐKXĐ : `x≠0`

`\(\Leftrightarrow\dfrac{6\left(2x-10\right)}{24}=\dfrac{120}{24}+\dfrac{4\left(2-2x\right)}{24}\)

`=> 6(2x-10) =120 + 4(2-2x)`

`<=>12x - 60 = 120 +  8 - 8x`

`<=> 12x +8x=120 +8+60`

`<=> 20x= 188`

`<=>x=188/20=47/5 (tm)`

Answer 2

=> 6(2x-10) = 4(5+2-2x)

=> 12x-60=20+8-8x

=> 12x-60=28-8x

=>20x=28+60

=> 20x=88

=> x = 88/20 = 4,4

Answer 3

\(\dfrac{2x-10}{4}=5+\dfrac{2-2x}{6}\)

\(\Leftrightarrow\dfrac{3\left(2x-10\right)}{12}=\dfrac{60}{12}+\dfrac{2\left(2-2x\right)}{12}\)

\(\Leftrightarrow6x-30=60+4-4x\)

\(\Leftrightarrow6x-30-60-4+4x=0\)

\(\Leftrightarrow10x-94=0\)

\(\Leftrightarrow10x=94\)

\(\Leftrightarrow x=\dfrac{47}{5}\)

\(\text{Vậy phương trình trên có tập nghiệm là }S=\left\{\dfrac{47}{5}\right\}\)