2x+1/5=3y-2/7=2x+3y-1/6x
tìm x,y biết 2x+1/5=3y-2/7=2x+3y-1/6x
Tìm x,y biết: (2x+1)/5 = (3y-2)/7 = (2x+3y-1)/(6x)
(2x+1):5=(3y-2):7=(2x+3y-1):6x tìm x;y
2X+1/5=3y-2/7=2x+3y-1/6x
tìm x+y
tìmx,y,z biết
(2x+5)/5=(3y-2)/7=(2x+3y-1)/6x
Tìm x, y biết:
2x+1/5 = 3y-2/7 = 2x+3y-1/6x
cho x, y thỏa mãn : 2x+1/5=3y-2/7=2x+3y-1/6x. Tìm x, y
\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)