- Trường hợp 2x-1 > hoặc = 0 thì x>1/2, phương trình trở thành
2x - 1 = 16 <=> x = 17/2 (TMĐK)
- Trường hợp 2x -1 < 0 thì x < 1/2, phương trình trở thành
-(2x - 1) = 16 <=> -2x +1=16 <=> x = -15/2 (TMĐK)
Vậy S= {17/2;-15/2}
(đây là cách lớp 8 )
Giúp mình với nhé!
3/2.(x-1/2)-3/4=1/2x-1
5/2.(x-3/4)-1/2=1-2x
9/2-3(1/2x-1)-4=1/2x-2
5-3/4.(x-1/3)-4(x-2)=1-11/2
4/5.17-x-3/2x=13/4x
Mình cảm ơn!
1) (x + 1/2).(2/3 - 2x) = 0 2) 2/3x + 1/2x = 5/2 : 3 và 3/4 3) (2x - 3)(6 - 2x)= 0 4) -5(x + 1/5) - 1/2(x - 2/3) = 3/2x - 5/6
a,-2\3x+1\5=1\10
b,2|1\2x-3\8|-3\2=1\4
c,-5(x+1\5)-1\2(x-2\3)=3\2x-5\6
d,3(x-1\2)- 5(x+3\5)=-x+1\5
e,3\4-2.|2x-0,125|=2
f,2|1\2x-1\3|-3\2=1\4
g,4\5-1\2x=1\10
1) Tìm x biết :
a) ( 2x - 3/1/2 ) + 250% = 6,2
b) ( 25% - 4/1/2x ) - 2/1/2 . 4^2 = 5,25
c) ( 2x - 1 )^2 - 80 = 1
d) ( x - 1/2 ) . ( 2x + 3 ) > 0
1) 3 ( 3x + 2 ) + 2 ( 2x + 4 ) = 90
2) 5 ( x + 1 ) + 3 ( 2x + 1 ) = 65
3 ) 3 ( 4 + 3x ) + 5 ( 1 + 2x ) = 100
giải các bất phương trình sau và biểu diễn nghiệm trên trục số:
a)2x+2>4
b)3x+2.-5
c)10-2x>2
d)1-2x<3
e)10x+3-5x<=14x+12
f)(3x-1)<2x+4
g)4x-8>=3(2x-1)-2x+1
h)x^2-x(x+2)>3x-1
i)x+8>3x-1
j)3x-(2x+5)<=(2x-3)
k)(x-3)(x+3)<x(x+2)+3
l)2(3x-1)-2x<2x+1
m)3-2x/5>2-x/3
n)x-2/6-x-1/3<=x/2
o)x+1/3>2x-1/6-2
p)1+2x+1/3>2x-1/6-2
q)x+5/6-2x+1/3<=x+3/2
r)5x+4/6-2x-1/12>=4
tìm x : a (1/2+2x)(2x -3)=0
b 1/4 -(2x +1/2)^2 =0
a/ 2.(1/2x -1/3)-3/2=1/4
b/ (1/2+2x)(2x-3)=0
c/ (4x-5)(5/4x-2)=0
d/ 1/4-(2x+1/2)mũ hai=0
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Tìm x
1/2×4 + 1/4×6 + ....+ 1/[(2x-2) × 2x = 1/8
